Evan
Evan

Reputation: 537

Sort file name with delimiter in batch file

I need to sort the list of file names by their version number with least first, in windows batch script. The file names are like:

2_0_0to2_0_1
2_0_1_to2_0_2
...
2_0_12_to2_0_13
...

I've tried dir and sort in Windows but it seems to only look at char positions which wouldn't work in the case of double digits. In Linux, I've done this with: ls *.txt | sort -n -t _ -k1 -k2 -k3. How to do this on Windows. Please help. Thanks!

Upvotes: 0

Views: 1632

Answers (1)

Endoro
Endoro

Reputation: 37569

Try this:

@ECHO OFF &SETLOCAL ENABLEDELAYEDEXPANSION
FOR %%x IN (*) DO (
    FOR /f "tokens=1-6delims=_to" %%a IN ("%%~x") DO (
        SET "g1=0%%a"
        SET "g2=0%%b"
        SET "g3=0%%c"
        SET "g4=0%%d"
        SET "g5=0%%e"
        SET "g6=0%%f"
        SET "$!g1:~-2!!g2:~-2!!g3:~-2!!g4:~-2!!g5:~-2!!g6:~-2!=%%~x"
    )
)
FOR /f "tokens=2delims==" %%a IN ('set "$"') DO ECHO %%~a

Upvotes: 4

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