Reputation: 43
I have a some file with the following content
$ cat somefile
28 46 5d a2 26 7a 192 168 2 2
0 15 e c8 a8 a3 192 168 100 3
54 4 2b 8 c 26 192 168 20 3
As you can see the values in first six columns are represented in hex, the values in last four columns in decimal formats. I just want to add 0 to every single symbol hexidecimal value.
Thanks beforehand.
Upvotes: 3
Views: 168
Reputation: 58430
This might work for you (GNU sed):
sed 's/\b\S\s/0&/g' file
Finds a single non-space character and prepends a 0
.
Upvotes: 0
Reputation: 224964
This one should work out for you:
while read -a line
do
hex=(${line[@]:0:6})
printf "%02x " ${hex[@]/#/0x}
echo ${line[@]:6:4}
done < somefile
Example:
$ cat somefile
28 46 5d a2 26 7a 192 168 2 2
0 15 e c8 a8 a3 192 168 100 3
54 4 2b 8 c 26 192 168 20 3
$ while read -a line
> do
> hex=(${line[@]:0:6})
> printf "%02x " ${hex[@]/#/0x}
> echo ${line[@]:6:4}
> done < somefile
28 46 5d a2 26 7a 192 168 2 2
00 15 0e c8 a8 a3 192 168 100 3
54 04 2b 08 0c 26 192 168 20 3
Upvotes: 3
Reputation: 5063
Please try this too, if it helps (bash version 4.1.7(1)-release)
#!/bin/bash
while read line;do
arr=($line)
i=0
for num in "${arr[@]}";do
if [ $i -lt 6 ];then
if [ ${#num} -eq 1 ];then
arr[i]='0'${arr[i]};
fi
fi
i=$((i+1))
done
echo "${arr[*]}"
done<your_file
Upvotes: 0
Reputation: 77105
Here is a way with awk
if that is an option:
awk '{for(i=1;i<=6;i++) if(length($i)<2) $i=0$i}1' file
$ cat file
28 46 5d a2 26 7a 192 168 2 2
0 15 e c8 a8 a3 192 168 100 3
54 4 2b 8 c 26 192 168 20 3
$ awk '{for(i=1;i<=6;i++) if(length($i)<2) $i=0$i}1' file
28 46 5d a2 26 7a 192 168 2 2
00 15 0e c8 a8 a3 192 168 100 3
54 04 2b 08 0c 26 192 168 20 3
Upvotes: 1