CODEWITHSUNDEEP
php
user2288650
user2288650

Reputation: 450

DirectoryIterator still showing 3 files when the forder is empty

I have following code to count number of files in a folder using php

$x=0;
$filepath=$uplaod_drive."Workspace/12345";
$dir = new DirectoryIterator($filepath);
foreach($dir as $file ){
  $x++;
}

But even if the folder is empty it show 3 files are there and if the folder has 8 files it show 11 files.

I would be very thankful if someone could explain this ..Thanks.

Upvotes: 0

Views: 587

Answers (2)

Ioannis Lalopoulos
Ioannis Lalopoulos

Reputation: 1511

if you want to count only regular files:

$x=0;
$filepath=$uplaod_drive."Workspace/12345";
$dir = new DirectoryIterator($filepath);
foreach($dir as $file ){
  if ($file->isFile()) $x++; 
}

or if you want to skip the directories:

$x=0;
$filepath=$uplaod_drive."Workspace/12345";
$dir = new DirectoryIterator($filepath);
foreach($dir as $file ){
  if (!$file->isDir()) $x++; 
}

or if you want to skip the dot files:

$x=0;
$filepath=$uplaod_drive."Workspace/12345";
$dir = new DirectoryIterator($filepath);
foreach($dir as $file ){
  if (!$file->isDot()) $x++; 
}

Upvotes: 2

shxfee
shxfee

Reputation: 5306

The DirectoryIterator is counting the current directory (denoted by '.') and the previous directory (denoted by '..') as $files. Debug your code like so. 

$x=0;
$filepath='C:\xampp\htdocs\\';
$dir = new DirectoryIterator($filepath);
foreach($dir as $file ){
    echo $file . "<br/>";
  $x++;
}
echo $x;

Then as mentioned in the comment above by @Prix you can skip if $file->isDot(), and if you dont want to count the directories then also skip if not $file->isFile().

$x=0;
$filepath='C:\xampp\htdocs\\';
$dir = new DirectoryIterator($filepath);
foreach($dir as $file ){
    if ($file->isDot() || !$file->isFile()) continue;
    //echo $file . "<br/>";
  $x++;
}
echo $x;

Upvotes: 0

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