CODEWITHSUNDEEP
c++
user1777711
user1777711

Reputation: 1744

C++ Copy String into Char String Array

below is my code

#include <stdio.h>
#include <string.h>
#include <iostream>

int main()
{
    std::string data;

    data = "hello world";

    char string[] = new char [data.length()+1];;
strcpy(string, data.c_str());


}

I got an error..

file.cpp: In function ‘int main()’:
file.cpp:14:46: error: initializer fails to determine size of ‘string’

What should i do as I want copy the content of string data into char string[]

Thanks for helping.

Upvotes: 1

Views: 6979

Answers (5)

Pierre Fourgeaud
Pierre Fourgeaud

Reputation: 14510

You should do :

char* string = new char[data.length()+1];
//  ^

strcpy take two pointers as argument. char string[] means you are declaring an array.

Here is the prototype of the function :

char *strcpy(char *dest, const char *src);

Upvotes: 0

oimitro
oimitro

Reputation: 1506

Try something like this : 

string Name="Hello FILE!"
int TempNumOne=Name.size();
char Filename[100];
for (int a=0;a<=TempNumOne;a++)
    {
        Filename[a]=Name[a];
    }

Upvotes: 0

nullptr
nullptr

Reputation: 11058

Use char *string, not char string[].

The char string[] means that you define an array, and size of the array should be evaluated from the initializer in compile-time.

Upvotes: 2

user123
user123

Reputation: 9071

In order to get it to compile, you'd have to use a char* instead of a char[]. char[] in this case requires a constant size, and since data is not a compile-time constant, the size cannot be determined.

Upvotes: 1

dinox0r
dinox0r

Reputation: 16039

Change to the following:

char* string = new char[data.size()+1];

Upvotes: 6

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