CODEWITHSUNDEEP
parsinghaskellabstract-syntax-tree
user2548080
user2548080

Reputation: 187

How do I parse Haskell source into an AST in Haskell?

I am trying to parse a Haskell source file into an AST. I'm new to parsers so I'm not sure how to make my own. I was just wondering if there is a function that takes a file and returns an AST. I also thought it might work to turn a file into a string using readFile and then parsing the string, but I still don't know where to go from there. Is there some well-known way to do this? If not, how can I do it myself?

Upvotes: 2

Views: 803

Answers (1)

Dirk Holsopple
Dirk Holsopple

Reputation: 8831

Try Language.Haskell.Meta.Parse. In particular, parseHsModule will parse an entire module for you. There are also functions for parsing smaller chunks, such as parseExp which parses an expression.

Upvotes: 3

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