CODEWITHSUNDEEP
c++c++11c++-chrono
Michael D
Michael D

Reputation: 1479

obtain current day using chrono

C++11 provide a function to return current time. However, I cannot find there is a function to return current day. And I use boost to do so. 

boost::gregorian::date TODAY = boost::gregorian::day_clock::local_day();

Is there any way to achieve the same result using chrono?

EDIT: What I want is to use time_point to represent current day. That means the hour,minute and second are zero 2013-07-31 00:00:00

Upvotes: 4

Views: 771

Answers (1)

Nicol Bolas
Nicol Bolas

Reputation: 473447

Chronos doesn't extend to date issues; that's really not it's purpose. The dividing line between date issues and "time" issues is the day. And Chrono doesn't define a day type.

But you could just divide the time in hours by 24. Or even better, define your own duration typedef and use that:

typedef std::duration<std::uint32_t, std::ratio<3600 * 24>> day;

Then just use a time_point with that type:

std::chrono::time_point<std::chrono::system_clock, day> day_getter;
day_getter.time_since_epoch();

Upvotes: 6

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