CODEWITHSUNDEEP
phpiosimageupload
deemi-D-nadeem
deemi-D-nadeem

Reputation: 2514

how to upload image in php using iOS

i am new in web services in php i don't now what is the behavior of ios to upload image so i write down my PHP code can anybody help me what is wrong in php code or there something wrong in ios code

$picName = $_FILES['name']['pic_data'];

move_uploaded_file($_FILES["file"]["tmp_name"], 'images/'.$picName);

Upvotes: 0

Views: 1720

Answers (3)

Yigang Wu
Yigang Wu

Reputation: 3592

You could refer the below link to know how to upload image and use mysql to manage it.

http://www.raywenderlich.com/13511/how-to-create-an-app-like-instagram-with-a-web-service-backend-part-12 http://www.raywenderlich.com/13541/how-to-create-an-app-like-instagram-with-a-web-service-backend-part-22

Upvotes: 0

deemi-D-nadeem
deemi-D-nadeem

Reputation: 2514

Thanx Alot i know what i do wrong so thanx to ernaidu and asad Mahmood

this Wrong::

$picName = $_FILES['name']['pic_data'];

move_uploaded_file($_FILES["file"]["tmp_name"], 'images/'.$picName);

This is right::

$picName = $_FILES['pic_data']['name'];

move_uploaded_file($_FILES["pic_data"]["tmp_name"], '../images/'.$picName);

Upvotes: 0

Asad
Asad

Reputation: 68

I think you must be sending like this:

xhrRegister.send({ file : selectedPhoto });

and you can get it in PHP like this:

if ($_FILES["file"]["error"] > 0) {
  // ERROR
} else {
  $filename = uniqid() . $_FILES["file"]["name"];
  $filetype = $_FILES["file"]["type"];
  move_uploaded_file($_FILES["file"]["tmp_name"], 'images/' . $filename);
}

Upvotes: 4

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