CODEWITHSUNDEEP
pythonsearchmultidimensional-arrayfind
alia
alia

Reputation: 1

searching an item in a multidimensional array in python

i have this multidimensional array in python.

hello = [(['b', 'y', 'e'], 3), (['h', 'e', 'l', 'l', 'o'], 5), (['w', 'o', 'r', 'l', 'd'], 5)]

and I wanted to find the index of number 3, I tried using hello.index(3) but won't work. Any solutions?

Upvotes: 0

Views: 12289

Answers (2)

Adem Öztaş
Adem Öztaş

Reputation: 21446

Try like this,

>>> [ i for i in hello if i[1] == 3 ]
[(['b', 'y', 'e'], 3)]

Upvotes: 0

roman
roman

Reputation: 117345

>>> [x[0] for x in hello if x[1] == 3][0]
['b', 'y', 'e']

if you need index of item, try

>>> [i for i, x in enumerate(hello) if x[1] == 3][0]
0

for multiple results just remove [0] at the end:

>>> hello.append((list("spam"), 3))
>>> hello
[(['b', 'y', 'e'], 3), (['h', 'e', 'l', 'l', 'o'], 5), (['w', 'o', 'r', 'l', 'd'], 5), (['s', 'p', 'a', 'm'], 3)]
>>> [x[0] for x in hello if x[1] == 3]
[['b', 'y', 'e'], ['s', 'p', 'a', 'm']]
>>> [i for i, x in enumerate(hello) if x[1] == 3]
[0, 3]
>>>

Upvotes: 5

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