Reputation: 6555
In Django I want to use a simple template tag to truncate data.
This is what I have so far:
@register.filter(name='truncate_simple')
def truncate_char_to_space(value, arg):
"""
Truncates a string after a given length.
"""
data = str(value)
if len(value) < arg:
return data
if data.find(' ', arg, arg+5) == -1:
return data[:arg] + '...'
else:
return data[:arg] + data[arg:data.find(' ', arg)] + '...'
But when I use it I get the following error:
{{ item.content|truncate_simple:5 }}
Error:
'ascii' codec can't encode character u'\u2013' in position 84: ordinal not in range(128)
Error is on line starting data = str(value)
Why?
Upvotes: 17
Views: 27987
Reputation: 652
import sys
reload(sys)
sys.setdefaultencoding('UTF8')
Upvotes: 4
Reputation: 12142
If you're using django and python 2.7 this fixes it for me:
from django.utils.encoding import python_2_unicode_compatible
@python_2_unicode_compatible
class Utente(models.Model):
see https://docs.djangoproject.com/en/dev/ref/utils/#django.utils.encoding.python_2_unicode_compatible
Upvotes: 29
Reputation: 568
try to use unicode() to convert value (instead of str()):
data = unicode(value)
Upvotes: 12
Reputation: 985
@max4ever 's answer works for me. also sometimes you should put this line in the head of python files:
from __future__ import unicode_literals
it can be helpful when solving unicode encoding issues like this one.
Upvotes: 6