CODEWITHSUNDEEP
haskellhaskell-src-exts
user2548080
user2548080

Reputation: 187

"parse" function in Language.Haskell.Exts.Parser?

There is a function called parse in the title module. It has a type signature 

parse :: String -> ParseResult ast

I have been working at it for a while and I can't figure out how to use it. I'm sure its something obvious but I am just not seeing it. Thanks in advance!

Upvotes: 1

Views: 286

Answers (1)

Austin T.
Austin T.

Reputation: 58

The Language.Haskell.Exts.Parser module handles parsing Haskell source code into an appropriate syntax tree. parse is a general function to handle parsing a String of Haskell source into an instance of the Parseable class. For an Exp (a Haskell expression), parse is defined as:

instance Parseable Exp where
    parse = parseExp

So, to use the parse function, just provide a type declaration if one cannot be inferred. For example, to parse the expression "5 + 5":

parse "5 + 5" :: ParseResult Exp

Which is equivalent to:

parseExp "5 + 5"

In ghci, they both return:

ParseOk (InfixApp (Lit (Int 5)) (QVarOp (UnQual (Symbol "+"))) (Lit (Int 5)))

Upvotes: 3

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