CODEWITHSUNDEEP
javaregex
l a s
l a s

Reputation: 3923

java regex extract numbers with boundary and optional space

I am trying to extract 12 and 15.

AB CD 12 ABC/15 DEF
.*\bAB CD\b\s?(\d+)\s?\bABC\b[/](\d+)\s?\bDEF\b

It is not working as i am not sure how to match exact words. I am trying to match exact words using boundary and it seems to be creating a problem.

I tried

.*\\bAB CD\\b\\s?(\\d+)\\s?\\bABC\\b[/](\\d+)\\s?\\bDEF\\b
.*\\bAB CD\\b\\s*(\\d+)\\s*\\bABC\\b[/](\\d+)\\s*\\bDEF\\b
.*\\bAB CD\\b[\\s]?(\\d+)[\\s]?\\bABC\\b[/](\\d+)[\\s]?\\bDEF\\b
.*\\bAB CD\\b[\\s]*(\\d+)[\\s]*\\bABC\\b[/](\\d+)[\\s]*\\bDEF\\b

thanks.

Upvotes: 0

Views: 291

Answers (4)

Akash
Akash

Reputation: 5012

.*\bAB CD\b\s?(\d+)\s?\bABC\b[/](\d+)\s?\bDEF\b
                           ^^^        ^^ you dont need these \b

Upvotes: 0

acdcjunior
acdcjunior

Reputation: 135762

Besides the expression being a little redundant, you must be doing something wrong, as your very first expression works:

import java.util.*;
import java.util.regex.*;
import java.lang.*;
 
class Main {
    public static void main (String[] args) throws java.lang.Exception {
        
        String currentLine = "AB CD 12 ABC/15 DEF";
        System.out.println("Current Line: "+ currentLine);
        Pattern p = Pattern.compile(".*\\bAB CD\\b\\s?(\\d+)\\s?\\bABC\\b[/](\\d+)\\s?\\bDEF\\b");
        Matcher m = p.matcher(currentLine);
        while (m.find()) {
            System.out.println("Matched: "+m.group(1));
            System.out.println("Matched: "+m.group(2));
        }
        
    }
}

And a demo link to prove: http://ideone.com/0tXFNu

Output:

Current Line: AB CD 12 ABC/15 DEF
Matched: 12
Matched: 15

So make sure you use m.group(NUMBER) to access each of the matched values.

Upvotes: 1

falsetru
falsetru

Reputation: 369064

What you want is just extract digits out of string, try following code:

Pattern p = Pattern.compile("\\d+");
Matcher m = p.matcher("AB CD 12 ABC/15 DEF");
while (m.find()) {
    System.out.println(m.group());
}

If you want string match exactly except digits:

Pattern p = Pattern.compile("AB\\s+CD\\s+(\\d+)\\s+ABC/(\\d+)\\s*DEF");
Matcher m = p.matcher("AB CD 12 ABC/15 DEF");
if (m.find()) {
    System.out.println(m.group(1));
    System.out.println(m.group(2));
}

Upvotes: 0

Casimir et Hippolyte
Casimir et Hippolyte

Reputation: 89557

You can use this:

"AB\\s*CD\\s*(\\d+)\\s*ABC/(\\d+)\\s*DEF"

Upvotes: 0

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