Reputation: 921
i have the following table
ID CATALOGUE SWID PARENTSWID LEVEL
1 1 1 1 0
2 1 2 1 1
3 1 3 1 1
4 1 4 2 2
5 1 5 4 3
6 1 6 5 4
7 2 2 2 0
8 2 3 2 1
So I want all elements (SWID)
which have the PARENTSWID= "1"
.
The root level is always "0
", and root element have the same SWID
and PARENTSWID
There are no boundaries for the depth of the tree.
Later I will have to restrict the search with the CATALOGUE
property, but for now I need an idea how to set this up.
So, has somebody done anything like this ? :)
Kind regards Semir
WITH cte as
(
SELECT ID, CATALOGUE, SWID, PARENTSWID, LEVEL
FROM table
WHERE PARENTSWID = 1
AND LEVEL = 0
UNION ALL
SELECT t.ID, t.CATALOGUE, t.SWID, t.PARENTSWID, t.LEVEL
FROM table t
JOIN CTE ON cte.ID = t.PARENTSWID
AND t.LEVEL= cte.LEVEL+1
)
SELECT ID, CATALOGUE, SWID, PARENTSWID, LEVEL FROM cte;
when trying this i get the error "unknown ISC error 336397226".
I have looked up this error and it means : 336397226 dsql_cte_cycle CTE '@1' has cyclic dependencies
My table has the same items as the one here
(I have tried it on IBWSQL with my DB selected)
Upvotes: 3
Views: 1026
Reputation: 1145
Here is my solution for Firebird SQL using Common Table Expressions.
CREATE TABLE STACKOVERFLOW0001 (
ID INTEGER,
CATALOUGE INTEGER,
SWID INTEGER,
PARENTSWID INTEGER,
"LEVEL" INTEGER
);
INSERT INTO STACKOVERFLOW0001 (ID, CATALOUGE, SWID, PARENTSWID, "LEVEL")
VALUES (1, 1, 1, 1, 0);
INSERT INTO STACKOVERFLOW0001 (ID, CATALOUGE, SWID, PARENTSWID, "LEVEL")
VALUES (2, 1, 2, 1, 1);
INSERT INTO STACKOVERFLOW0001 (ID, CATALOUGE, SWID, PARENTSWID, "LEVEL")
VALUES (3, 1, 3, 1, 1);
INSERT INTO STACKOVERFLOW0001 (ID, CATALOUGE, SWID, PARENTSWID, "LEVEL")
VALUES (4, 1, 4, 2, 2);
INSERT INTO STACKOVERFLOW0001 (ID, CATALOUGE, SWID, PARENTSWID, "LEVEL")
VALUES (5, 1, 5, 4, 3);
INSERT INTO STACKOVERFLOW0001 (ID, CATALOUGE, SWID, PARENTSWID, "LEVEL")
VALUES (6, 1, 6, 5, 4);
INSERT INTO STACKOVERFLOW0001 (ID, CATALOUGE, SWID, PARENTSWID, "LEVEL")
VALUES (7, 2, 2, 2, 0);
INSERT INTO STACKOVERFLOW0001 (ID, CATALOUGE, SWID, PARENTSWID, "LEVEL")
VALUES (8, 2, 3, 2, 1);
COMMIT WORK;
Query
WITH RECURSIVE cat (id,catalouge,swid,parentswid,lvl)
as
(
select id,catalouge,swid,parentswid,"LEVEL" from stackoverflow0001 as r
where r."LEVEL" = 0 -- Magic Happens here for Filtering, you can specify the Start of the recursive tree walk down from here.
union all
select r.id, r.catalouge, r.swid, r.parentswid,r."LEVEL" from stackoverflow0001 as r,cat
where cat.swid = r.parentswid -- This is what matches up the first query record to the child records
and r."LEVEL" > 0 -- Just an additional filter check for child records.
)
select * from cat
// You can also stick some where clauses here if you need
Output
ID CATALOUGE SWID PARENTSWID LVL
1 1 1 1 0
2 1 2 1 1
4 1 4 2 2
5 1 5 4 3
6 1 6 5 4
8 2 3 2 1
3 1 3 1 1
7 2 2 2 0
4 1 4 2 2
5 1 5 4 3
6 1 6 5 4
8 2 3 2 1
8 2 3 2 1
Upvotes: 2
Reputation: 44326
This works with sqlserver 2005+
DECLARE @PARENTSWID int = 1
;WITH cte as
(
SELECT ID, CATALOGUE, SWID, PARENTSWID, LEVEL
FROM table
WHERE PARENTSWID = @PARENTSWID
AND LEVEL = 0
UNION ALL
SELECT t.ID, t.CATALOGUE, t.SWID, t.PARENTSWID, t.LEVEL
FROM table t
JOIN CTE ON cte.ID = t.PARENTSWID
AND t.LEVEL = cte.LEVEL +1
)
SELECT ID, CATALOGUE, SWID, PARENTSWID, LEVEL FROM cte
OPTION (MAXRECURSION 0)
See this fiddle.
Upvotes: 4