CODEWITHSUNDEEP
mysqlsql
user2003356
user2003356

Reputation: 455

Mysql - how to sort the date format with am/pm

Please check the query.

SELECT DATE_FORMAT( CAST( CONCAT( table.date,  " ", table.time ) ) ,  '%p' ) 
FROM table AS table

Error:
[hash]1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '), '%p') FROM exp_visitorsday as vd LIMIT 0, 30' at line 2

I have tried this query in following cases.

SELECT DATE_FORMAT( CAST( CONCAT( table.date,  " ", table.time ) as datetimecol ) as datetimecol,  '%p' ) 
FROM table AS table

SELECT DATE_FORMAT( CAST( CONCAT( table.date,  " ", table.time ) as datetimecol ),  '%p' ) 
FROM table AS table

Sample data:

table.date => 01-08-2013
table.time => 10:00 AM

How to do query? What's a problem in this query?

Upvotes: 1

Views: 780

Answers (1)

TNguyen
TNguyen

Reputation: 176

You can:

SELECT * 
FROM (
    SELECT DATE_FORMAT( 
                                    CONCAT( SUBSTRING_INDEX( "01-08-2013", "-", -1), "-",  
                                    SUBSTRING_INDEX(SUBSTRING_INDEX( "01-08-2013", "-", 2), "-", -1), "-", 
                                    SUBSTRING_INDEX( "01-08-2013", "-", 1), " ", 
                                    IF( SUBSTRING_INDEX( "10:00 PM", " ", -1) = "AM", 
                                                SUBSTRING_INDEX( "10:00 AM", " ", 1),  
                                                CONCAT( SUBSTRING_INDEX(SUBSTRING_INDEX( "10:00 AM", " ", 1), ":", 1) + 12, ":", SUBSTRING_INDEX(SUBSTRING_INDEX( "10:00 AM", " ", 1), ":", -1))  )) , '%Y-%m-%d %h:%i') AS datformat ) AS tmp
ORDER BY tmp.datformat;

Explain:

SELECT SUBSTRING_INDEX( "01-08-2013", "-", 1); #Day
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX( "01-08-2013", "-", 2), "-", -1);#Month
SELECT SUBSTRING_INDEX( "01-08-2013", "-", -1); #Year

Upvotes: 1

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