CODEWITHSUNDEEP
pythonpandas
d1337
d1337

Reputation: 2753

How to assign a name to the size() column?

I am using .size() on a groupby result in order to count how many items are in each group.

I would like the result to be saved to a new column name without manually editing the column names array, how can it be done?

This is what I have tried:

grpd = df.groupby(['A','B'])
grpd['size'] = grpd.size()
grpd

and the error I got:

TypeError: 'DataFrameGroupBy' object does not support item assignment (on the second line)

Upvotes: 109

Views: 102447

Answers (5)

Mykola Zotko
Mykola Zotko

Reputation: 17892

You can set the as_index parameter in groupby to False to get a DataFrame instead of a Series:

df = pd.DataFrame({'A': ['a', 'a', 'b', 'b'], 'B': [1, 2, 2, 2]})

df.groupby(['A', 'B'], as_index=False).size()

Output:

   A  B  size
0  a  1     1
1  a  2     1
2  b  2     2

Upvotes: 9

jezrael
jezrael

Reputation: 863361

You need transform size - len of df is same as before:

Notice:

Here it is necessary to add one column after groupby, else you get an error. Because GroupBy.size count NaNs too, what column is used is not important. All columns working same.

import pandas as pd

df = pd.DataFrame({'A': ['x', 'x', 'x','y','y']
                , 'B': ['a', 'c', 'c','b','b']})
print (df)
   A  B
0  x  a
1  x  c
2  x  c
3  y  b
4  y  b

df['size'] = df.groupby(['A', 'B'])['A'].transform('size')
print (df)
   A  B  size
0  x  a     1
1  x  c     2
2  x  c     2
3  y  b     2
4  y  b     2

If need set column name in aggregating df - len of df is obviously NOT same as before:

import pandas as pd

df = pd.DataFrame({'A': ['x', 'x', 'x','y','y']
                , 'B': ['a', 'c', 'c','b','b']})
print (df)
   A  B
0  x  a
1  x  c
2  x  c
3  y  b
4  y  b

df = df.groupby(['A', 'B']).size().reset_index(name='Size')
print (df)
   A  B  Size
0  x  a     1
1  x  c     2
2  y  b     2

Upvotes: 55

user8403237
user8403237

Reputation:

lets say n is the name of dataframe and cst is the no of items being repeted. Below code gives the count in next column

cstn=Counter(n.cst)
cstlist = pd.DataFrame.from_dict(cstn, orient='index').reset_index()
cstlist.columns=['name','cnt']
n['cnt']=n['cst'].map(cstlist.loc[:, ['name','cnt']].set_index('name').iloc[:,0].to_dict())

Hope this will work

Upvotes: 0

Sealander
Sealander

Reputation: 3671

The .size() built-in method of DataFrameGroupBy objects actually returns a Series object with the group sizes and not a DataFrame. If you want a DataFrame whose column is the group sizes, indexed by the groups, with a custom name, you can use the .to_frame() method and use the desired column name as its argument. 

grpd = df.groupby(['A','B']).size().to_frame('size')

If you wanted the groups to be columns again you could add a .reset_index() at the end.

Upvotes: 125

Dan Allan
Dan Allan

Reputation: 35265

The result of df.groupby(...) is not a DataFrame. To get a DataFrame back, you have to apply a function to each group, transform each element of a group, or filter the groups.

It seems like you want a DataFrame that contains (1) all your original data in df and (2) the count of how much data is in each group. These things have different lengths, so if they need to go into the same DataFrame, you'll need to list the size redundantly, i.e., for each row in each group.

df['size'] = df.groupby(['A','B']).transform(np.size)

(Aside: It's helpful if you can show succinct sample input and expected results.)

Upvotes: 44

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