CODEWITHSUNDEEP
javawicket
newtojava
newtojava

Reputation: 33

Wicket exception on page redirect

I have a wicket page, and on the form submit I do a redirect to another page. I have this:

@Override
protected void onSubmit()
{
    //Do something
    response.sendRedirect(previousPageUrl);
}

The page was redirected correctly, but I got this exception:

[org.apache.wicket.protocol.http.WebResponse] [Unable to redirect to:..., HTTP Response has already been committed.]
[org.apache.wicket.protocol.http.WicketFilter] [closing the buffer error]
java.lang.IllegalStateException: Committed
    at org.eclipse.jetty.server.Response.resetBuffer(Response.java:1059) ~[na:na]
    at org.eclipse.jetty.server.Response.sendRedirect(Response.java:449) ~[na:na]
    at org.apache.wicket.protocol.http.WebResponse.sendRedirect(WebResponse.java:299) ~[wicket-1.4.17.jar:1.4.17]
    at org.apache.wicket.protocol.http.WebResponse.redirect(WebResponse.java:250) ~[wicket-1.4.17.jar:1.4.17]
    at org.apache.wicket.protocol.http.BufferedWebResponse.close(BufferedWebResponse.java:67) ~[wicket-1.4.17.jar:1.4.17]

I already tried to add this line before my sendRedirect() call, but it didn't help:

getRequestCycleSettings().setRenderStrategy(IRequestCycleSettings.ONE_PASS_RENDER);

Upvotes: 0

Views: 1689

Answers (2)

svenmeier
svenmeier

Reputation: 5681

You have to interrupt Wicket's request processing:

 throw new RedirectToUrlException(previousPageUrl);

Upvotes: 1

user2507946
user2507946

Reputation: 584

My first initial impression on your code is that in your // do something you might have written something to the response object. You can try to do either commment those codes first to isolate the problem or paste the whole // do something here so that we can you help you better.

Upvotes: 1

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