CODEWITHSUNDEEP
python
user2644430
user2644430

Reputation: 47

Syntax Error in Python 3.2.1: Unable to write an exception to a ValueError

I'm new at python and recently I've been trying to write a code for a hangman game: a part of the MIT OCW course: Introduction to Computer Science and Programming. My code goes as follows:

def write_words (word, al):
    neww = (list(word))
    newal = (list(al))
    x = 0
    while (x <= (len(newal))):
        z = newal[x]
        y = neww.index(z)
        except ValueError:
            pass
        x = x + 1
        return (z)
        return (y)

when I call the function using write_words ("word", "abcdefghijklmnopqrstuvwxy") I still get the ValueError:'a' is not in list, that is supposed to be corrected with the exception. I 've been trying to figure out the problem, and apparently is a Syntax error. Please, I would be very grateful with any help. My python version is the 3.2.1

Upvotes: 1

Views: 115

Answers (1)

Sukrit Kalra
Sukrit Kalra

Reputation: 34493

You don't have a try statement there. The format is try-except. Something like this.

try:
     a = 25 / 0
except ZeroDivisionError:
    print("Not Possible")


# Output: Not Possible

Upvotes: 4

Related Questions