CODEWITHSUNDEEP
phppreg-match
user2426701
user2426701

Reputation:

PHP's preg_match() returns only the match value

I am doing the following:

$text = 'L\' utente _{nickname} ti ha invitato a giocare';

$text_vars = preg_match('#\_{(.*?)\}#', $text, $matches);

returns:

Array
(
    [0] => _{nickname}
    [1] => nickname
)

How can it be made to only return the following?

Array
(
    [0] => nickname
)

Upvotes: 5

Views: 23154

Answers (3)

Виктор Пупкин
Виктор Пупкин

Reputation: 127

try this

$text = 'L\' utente _{nickname} ti ha invitato a giocare';
$text_vars = preg_match('#\_{(.*?)\}#', $text, $matches) ? $matches[1] : '';

echo $text_vars;

Upvotes: 9

Casimir et Hippolyte
Casimir et Hippolyte

Reputation: 89557

You can use a lookahead (?=..) and a lookbehind (?<=..) (or a match reset \K)

$text_vars = preg_match('~(?<=_{)[^}]++(?=})~', $text, $match);

Or

$text_vars = preg_match('~_{\K[^}]++(?=})~', $text, $match);

Upvotes: 1

hjpotter92
hjpotter92

Reputation: 80639

From preg_match() documentation:

If matches is provided, then it is filled with the results of search. $matches[0] will contain the text that matched the full pattern, $matches[1] will have the text that matched the first captured parenthesized subpattern, and so on.

For the desired behavior, use array_shift() like this:

$text = 'L\' utente _{nickname} ti ha invitato a giocare';
$text_vars = preg_match('#\_{(.*?)\}#', $text, $matches);
$temp = array_shift( $matches );

Upvotes: 11

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