CODEWITHSUNDEEP
c++visual-c++
AndrewR
AndrewR

Reputation: 10889

Why does this pointer to C++ function code generate a compile error?

Can anyone solve this? I can’t seem to find the solution anywhere, but I see no logical reason why the line below (with the comment showing the compile error) should be a problem.

Note: This question is a derivative of How can a C++ base class determine at runtime if a method has been overridden?

class MyClass
{
        typedef void (MyClass::*MethodPtr)();  


        virtual void Method()
        {
                MethodPtr a = &MyClass::Method; // legal
                MethodPtr b = &Method;  // error C2276: ‘&’ : illegal operation on bound member function expression

                if (a == b)     // this method has not been overridden?
                        throw “Not overridden”;
        }
};

Upvotes: 1

Views: 3350

Answers (1)

Vijay Mathew
Vijay Mathew

Reputation: 27164

ISO C++ forbids taking the address of an unqualified or parenthesized non-static member function to form a pointer to member function. This takes care of name mangling. So what you are trying to do will not work in a standards compliant C++ compiler.

Upvotes: 12

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