CODEWITHSUNDEEP
djangodjango-templates
David542
David542

Reputation: 110203

How to only get first object in template

I have the following code, where I get all problem notes.

{% for n in task.task_notes.all %}
    {% if n.is_problem %}
        <li>{{ n }}</li>
    {% endif %}
{% endfor %}

How would I only get the first problem note? Is there a way to do that in the template?

Upvotes: 1

Views: 1289

Answers (3)

alecxe
alecxe

Reputation: 473873

Assuming you need all of the tasks in the template somewhere else.

You can make a reusable custom filter (take a look at first filter implementation btw):

@register.filter(is_safe=False)
def first_problem(value):
    return next(x for x in value if x.is_problem)

Then, use it in the template this way:

{% with task.task_notes.all|first_problem as problem %}
    <li>{{ problem }}</li>
{% endwith %}

Hope that helps.

Upvotes: 2

Paulo
Paulo

Reputation: 103

use this code in the loop:

{% if forloop.counter == 1 %}{{ n }}{% endif %}

Upvotes: 0

Adri&#225;n
Adri&#225;n

Reputation: 6255

In the view:

context["problem_tasks"] = Task.objects.filter(is_problem=True)
# render template with the context

In the template:

{{ problem_tasks|first }}

first template filter reference.

Would be even better, if you dont need the other problem tasks at all (from 2nd to last):

context["first_problem_task"] = Task.objects.filter(is_problem=True)[0]
# render template with the context

Template:

{{ first_problem_task }}

Upvotes: 4

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