CODEWITHSUNDEEP
javainheritancecompiler-errors
Mat.S
Mat.S

Reputation: 1854

Compile Error Inheritance

I have the following code and it will not compile. 

public class P {
    private int num;
    P(int n) {
        this.num = n;
    }
}

public class Q extends P {
    private int i;
    public Q() {
        i = 0;
    }
}

Fix the second method so that it can compile.

Upvotes: 1

Views: 207

Answers (3)

Mohsin Shaikh
Mohsin Shaikh

Reputation: 504

In the code the compiler write the super() keyword in the Q class that time control will go the P class and it call the constructor, but P class has a parameter constructor.so you can add super() keyword with the any number because P class constructor has a parameter of int type.

  class P {
  private int num;
  P(int n) {
    this.num = n;
   }
  }
 public class Q extends P {
  private int i;
  public Q() {
    super(20);
    i = 0;
   }
     }

Upvotes: 0

arshajii
arshajii

Reputation: 129477

Invoke the super constructor:

public Q() {
    super(42);  // <--
    i = 0;
}

You can read more about super here.

Upvotes: 1

Jigar Joshi
Jigar Joshi

Reputation: 240860

You need to add default constructor in P to make it compile

P() {
  this.num = 0; // some default value
}

Upvotes: 1

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