Reputation: 2928
I'm working on a NLP project based on Python/NLTK with non-english unicode text. For that, I need to search unicode string inside a sentence.
There is a .txt file saved with some non-english unicode sentences. Using NLTK PunktSentenceTokenizer i broke them and saved in a python list.
sentences = PunktSentenceTokenizer().tokenize(text)
Now i can iterate through list and get each sentence
separately.
What i need to do is go through that sentence
and identify which word has the given unicode characters.
Example -
sentence = 'AASFG BBBSDC FEKGG SDFGF'
Assume above text is non-english unicode and i need to find words ending with GF
then return whole word (may be index of that word).
search = 'SDFGF'
Similarly i need to find words starting with BB
get the word of it.
search2 = 'BBBSDC'
Upvotes: 0
Views: 1321
Reputation: 169563
If I understand correctly, you just have to split up the sentence into words, loop over each one and check if it ends or starts with the required characters, e.g:
>>> sentence = ['AASFG', 'BBBSDC', 'FEKGG', 'SDFGF']
>>> [word for word in sentence.split() if word.endswith("GF")]
['SDFGF']
sentence.split()
could probably be replaced with something like nltk.tokenize.word_tokenize(sentence)
Update, regarding comment:
How can get word in-front of that and behind it
The enumerate
function can be used to give each word a number, like this:
>>> print list(enumerate(sentence))
[(0, 'AASFG'), (1, 'BBBSDC'), (2, 'FEKGG'), (3, 'SDFGF')]
Then if you do the same loop, but preserve the index:
>>> results = [(idx, word) for (idx, word) in enumerate(sentence) if word.endswith("GG")]
>>> print results
[(2, 'FEKGG')]
..you can use the index to get the next or previous item:
>>> for r in results:
... r_idx = r[0]
... print "Prev", sentence[r_idx-1]
... print "Next", sentence[r_idx+1]
...
Prev BBBSDC
Next SDFGF
You'd need to handle the case where the match the very first or last word (if r_idx == 0
, if r_idx == len(sentence)
)
Upvotes: 1