Reputation: 6544
I have a string "RowNumber5", now i want to get the numeric value "5" from that string using Javascript.
Note: Numeric value will be always at the end, after alphabets, that means numeric value will never occur in between alphabets. Example -
Result45 - Yes
Result45Abc - Never
I can get this "5" by some thing like this
var t = "Ruby12";
var y = parseInt(t.split('').reverse().join(""));
if(!isNaN(y)) {
y = y.toString().split('').reverse().join("");
}
else {
y = "";
}
console.log(y);
Any shot way? or Better approach for this ?
Upvotes: 3
Views: 3509
Reputation: 3106
This is what regexes were made for!
var matches = /\d+$/.exec("Ruby12");
matches[0]; //returns 12
var matches = /\d+$/.exec("sfwfewcsd098");
matches[0]; //returns 098
var matches = /\d+$/.exec("abc"); //matches returns null
Upvotes: 4
Reputation: 4876
Try using this regular expression
var s = "gdgdfg45";
var matches = s.match(/\d+$/);
console.log(matches[0]);
Upvotes: 1
Reputation: 18861
Here's a regex solution:
// input string
var t = "Ruby12";
var num = null;
var match = t.match(/([0-9]+)$/);
if(match!=null) num = parseInt(match[1]);
// num now contains null or number
// debug
console.log(num);
Upvotes: 1
Reputation: 3224
I would go with the divide and conquer method, working through all strings that may contain numbers:
var t = "Ruby12";
function get_numbers(str) {
var parts = str.split(""), nums = "";
for(var i = 0, len = parts.length; i < len; i++) {
nums += (isNaN(parts[i])) ? "" : parts[i].toString();
}
return(nums);
}
var numbers = get_numbers(t);
alert(numbers);
Which would give you "12".
Upvotes: 0