CODEWITHSUNDEEP
pythonpython-3.xtkinterruntime-error
fozbstuios
fozbstuios

Reputation: 373

Why am I getting 'module' object is not callable in python 3?

First, all relevant code

main.py 

import string
import app
group1=[ "spc", "bspc",",","."]#letters, space, backspace(spans mult layers)
# add in letters one at a time
for s in string.ascii_lowercase:
    group1.append(s)
group2=[0,1,2,3,4,5,6,7,8,9, "tab ","ent","lAR" ,"rAR" , "uAR", "dAR"]
group3= []
for s in string.punctuation:
    group3.append(s)#punc(spans mult layers)
group4=["copy","cut","paste","save","print","cmdW","quit","alf","sWDW"] #kb shortcut
masterGroup=[group1,group2,group3,group4]
myApp =app({"testFKey":[3,2,2]})

app.py

import tkinter as tk
import static_keys
import dynamic_keys
import key_labels
class app(tk.Frame):

    def __init__(inputDict,self, master=None,):
        tk.Frame.__init__(self, master)
        self.grid(sticky=tk.N+tk.S+tk.E+tk.W)
        self.createWidgets(self, inputDict)
    def createWidgets(self,inDict):
        top=self.winfo_toplevel()
        top.rowconfigure(0, weight=1)
        top.columnconfigure(0, weight=1)
        self.rowconfigure(0, weight=1)
        self.columnconfigure(0, weight=1)
        tempDict = {}
        for k,v in inDict.items():
                if 1<=v[0]<=3:
                    tempDict[k] = static_keys(*v[1:])
                elif v[0] ==4:
                    tempDict[k] = dynamic_keys(k,*v[1:])
                elif  v[0]==5:
                    tempDict[k] = key_labels(*v[1:])
        for o in tempDict:
            tempDict[o].grid()
        return tempDict

static_keys.py

import tkinter
class static_keys(tkinter.Label):
    """class for all keys that just are initiated then do nothing
    there are 3 options
    1= modifier (shift etc)
    2 = layer
    3 = fkey, eject/esc"""
    def __init__(t,selector,r,c,parent,self ):
        if selector == 1:
            tkinter.Label.__init__(master=parent, row=r, column=c, text= t, bg ='#676731')
        if selector == 2:
            tkinter.Label.__init__(master=parent, row=r, column=c, text= t, bg ='#1A6837')
        if selector == 3:
            tkinter.Label.__init__(master=parent, row=r, column=c, text= t, bg ='#6B6966')

Now for a description of the problem. When I run main.py in python3, I get the error

File "Desktop/kblMaker/main.py", line 13, in <module>
myApp =app({"testFKey":[3,2,2]})
TypeError: 'module' object is not callable

Upvotes: 12

Views: 56790

Answers (4)

hassan bazai
hassan bazai

Reputation: 459

The best way to fix this problem is: Go to Gradle, build (Madulus) and below the buildTypes, type the following code and sync the project.

viewBinding {
    enabled = true
}

Now you can access to the binding. If the xml layout is activity_main.xml, it means the binding is ActivityMainBinding.

Upvotes: 0

abarnert
abarnert

Reputation: 365657

The problem, as both F.J and Tadeck already explained, is that app is the module app, and app.app is the class app defined in that module.

You can get around that by using from app import app (or, if you must, even from app import *), as in Tadeck's answer, or by explicitly referring to app.app instead of just app, as in F.J's answer.

If you rename the class to App, that won't magically fix anything—you will still have to either from app import App or refer to app.App—but it will make the problem a whole lot more obvious. And make your code less confusing after you've fixed the problem, too.

This is part of the reason that PEP 8 recommends that:

Modules should have short, all-lowercase names.

…

Almost without exception, class names use the CapWords convention.

That way, there's no way to mix them up.

Upvotes: 2

Andrew Clark
Andrew Clark

Reputation: 208425

You have a module named app that contains a class named app. If you just do import app in main.py then app will refer to the module, and app.app will refer to the class. Here are a couple of options:

  • Leave your import statement alone, and use myApp = app.app({"testFKey":[3,2,2]}) inside of main.py
  • Replace import app with from app import app, now app will refer to the class and myApp = app({"testFKey":[3,2,2]}) will work fine

Upvotes: 33

Tadeck
Tadeck

Reputation: 137310

In main.py change second line to:

from app import app

The issue is you have app module and app class within it. But you are importing module, not the class from it:

myApp = app({"testFKey": [3, 2, 2]})

(you can also instead replace "app" inside line above into "app.app")

Upvotes: 10

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