Reputation: 87
I am using a Spry tabbed panel for an HTML base site.
I want to open fancybox, by clicking on a tab (four tabs in total). Once the user fills the fancybox form, only that particular tab panel content should be open.
Is this possible? Below is my code.
<div id="TabbedPanels1" class="TabbedPanels">
<ul class="TabbedPanelsTabGroup">
<li class="TabbedPanelsTab" tabindex="0">Tab 1</li>
<li class="TabbedPanelsTab" tabindex="0">Tab 2</li>
<li class="TabbedPanelsTab" tabindex="0">Tab 1</li>
<li class="TabbedPanelsTab" tabindex="0">Tab 2</li>
</ul>
<div class="TabbedPanelsContentGroup">
<div class="TabbedPanelsContent">Content 1</div>
<div class="TabbedPanelsContent">Content 2</div>
<div class="TabbedPanelsContent">Content 3</div>
<div class="TabbedPanelsContent">Content 4</div>
</div>
</div>
<script type="text/javascript">
var TabbedPanels1 = new Spry.Widget.TabbedPanels("TabbedPanels1");
</script>
I want to a form to be filled on tab #2 in fancy box. Once user fill that form and submit successfully after that only tab panel content should be opened.
Upvotes: 0
Views: 210
Reputation:
As you have not posted any code ..I can tell only logic .. U can get the selectedtab index by
var index= ($tabs.tabs('option', 'selected'));
and then you compare your index with the fetched index and if it matches then open your fancybox by
$(".fancy").fancybox().trigger('click');
and you can write your own function on sumbit/close of fancybox
$("<YOUR-SELECTOR>").fancybox({
onClosed: function() {
// your own functions
});
});
Upvotes: 1