Reputation: 1695
I read this link Converting 8 bit color into RGB value
Then I tried the VB.NET code like the following:
Private Sub picturebox1_MouseDown(ByVal sender As Object, _
ByVal e As System.Windows.Forms.MouseEventArgs) _
Handles picturebox1.MouseDown
Dim bm As New Bitmap(picturebox1.Image)
Dim Red As Byte = bm.GetPixel(e.X, e.Y).R
Dim Green As Byte = bm.GetPixel(e.X, e.Y).G
Dim Blue As Byte = bm.GetPixel(e.X, e.Y).B
Dim ColorNumber As Byte = ((Red / 32) << 5) + ((Green / 32) << 2) + (Blue / 64)
' Show Byte Number of color
MsgBox(ColorNumber)
MsgBox(Red & ":" & Green & ":" & Blue)
Red = (ColorNumber >> 5) * 32
Green = ((ColorNumber >> 2) << 3) * 32
Blue = (ColorNumber << 6) * 64
MsgBox(Red & ":" & Green & ":" & Blue)
End Sub
But when one pixel is selected, an error occurs:
Arithmetic operation resulted in an overflow.
How do I get a byte value of an image with 256 colors (8 bits), and then restore the (conversion) resulting byte value into the RGB value.
Thanks :)
Upvotes: 0
Views: 2783
Reputation: 6764
Your ColorNumber has been declared as a Byte, which can only store values from 0 to 255... Change the code to this:
Dim ColorNumber As Int32 = ((Red / 32) << 5) + ((Green / 32) << 2) + (Blue / 64)
Also, since you're using .Net you can just get the color with this function:
Dim color As Color = Color.FromRgb(Red, Green, Blue)
Upvotes: 1