CODEWITHSUNDEEP
pythonuser-interfaceconsolepopenpythonw
sbirch
sbirch

Reputation: 911

Running a process in pythonw with Popen without a console

I have a program with a GUI that runs an external program through a Popen call:

p = subprocess.Popen("<commands>" , stdout=subprocess.PIPE , stderr=subprocess.PIPE , cwd=os.getcwd())
p.communicate()

But a console pops up, regardless of what I do (I've also tried passing it NUL for the file handle). Is there any way to do that without getting the binary I call to free its console?

Upvotes: 30

Views: 21824

Answers (6)

udoline
udoline

Reputation: 81

The Python 'subprocess' Attribute shell=True

works on window 11

result = subprocess.run(['nslookup', '2.16.206.132'], shell=True, capture_output=True, text=True)
print(result.stdout)

The process is executed without open a shell-console. This runs much more faster as like with shell=False ... :)

The result is here:

Server:  OpenWrt.lan
Address:  192.168.1.1

Name:    a2-16-206-132.deploy.static.akamaitechnologies.com
Address:  2.16.206.132

Upvotes: 0

interjay
interjay

Reputation: 110108

From here:

import subprocess

def launchWithoutConsole(command, args):
    """Launches 'command' windowless and waits until finished"""
    startupinfo = subprocess.STARTUPINFO()
    startupinfo.dwFlags |= subprocess.STARTF_USESHOWWINDOW
    return subprocess.Popen([command] + args, startupinfo=startupinfo).wait()

if __name__ == "__main__":
    # test with "pythonw.exe"
    launchWithoutConsole("d:\\bin\\gzip.exe", ["-d", "myfile.gz"])

Note that sometimes suppressing the console makes subprocess calls fail with "Error 6: invalid handle". A quick fix is to redirect stdin, as explained here: Python running as Windows Service: OSError: [WinError 6] The handle is invalid

Upvotes: 39

ErnestoQ
ErnestoQ

Reputation: 129

According to Python 2.7 documentation and Python 3.7 documentation, you can influence how Popen creates the process by setting creationflags. In particular, the CREATE_NO_WINDOW flag would be useful to you.

variable = subprocess.Popen(
   "CMD COMMAND", 
   stdout = subprocess.PIPE, creationflags = subprocess.CREATE_NO_WINDOW
)

Upvotes: 6

Liam
Liam

Reputation: 6439

just do subprocess.Popen([command], shell=True)

Upvotes: 10

Devon Dieffenbach
Devon Dieffenbach

Reputation: 91

This works nicely in the win32api. The other solutions were not working for me. 

import win32api
chrome = "\"C:\\Program Files (x86)\\Google\\Chrome\\Application\\chrome.exe\""
args = "https://stackoverflow.com"

win32api.WinExec(chrome + " " + args)

Upvotes: 1

ThantiK
ThantiK

Reputation: 1602

You might be able to just do subprocess.Popen([command], shell=False).

That's what I use anyways. Saves you all the nonsense of setting flags and whatnot. Once named as a .pyw or run with pythonw it shouldn't open a console.

Upvotes: -1

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