CODEWITHSUNDEEP
phpdatestrtotime
MathieuB
MathieuB

Reputation: 527

How can I do addition with time variable in php

I was thinking this should be simple.

$m_time1 = strtotime('1:00:00');
$m_time2 = strtotime('5:30:00');
$m_total = $m_time1 + $m_time2;

echo date('h:i:s', $m_total);

The result is 3:30:00 but should be 6:30:00

Any clue why?

Upvotes: 0

Views: 1857

Answers (1)

Bad Wolf
Bad Wolf

Reputation: 8349

strtotime() produces a unix timestamp which represents the number of seconds between the time provided and January 1st 1970. Since you didn't specify a date in your function call, it assumes the current date at the time you passed to the function.

As a result your code above, run today produces an output of 

$m_time1 = 1376024400
$m_time2 = 1376040600

When you add these together it results in a "time" of 3:30 AM in the year 2057.

To avoid this happening, you need to escape subtract the timestamp for "today" from the timestamps before adding them and then add it back again after the addition.

$today = strtotime("TODAY");
$m_time1 = strtotime('1:00:00') - $today;
$m_time2 = strtotime('5:30:00') - $today;
$m_total = $m_time1 + $m_time2 + $today;

echo date('h:i:s', $m_total);

The above code echos 6:30:00.

PHPFiddle Example

Upvotes: 2

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