Reputation: 465
I'm trying to capture from PHPUnit output the file path and the error line with a condition.
This is my output and non-working (obviously:) pattern:
/path/includes/exception.php:7
/path/things-i-care-about/es/somefile.php:132
/path/things-i-care-about/es/somefile.php:121
/path/things-i-care-about/es/somefile.php:54
/path/things-i-care-about/es/somefile.php:60
/path/things-i-care-about/es/somefile.php:41
/path/things-i-care-about/es/somefile.php:47
/path/things-i-care-about/testfile.php:26
Pattern: /((?!exception).*.php):(\d.*)/gs
What I tried is negating any line that has "exception" in it, but my regex didn't quite work.
What am I doing wrong?
Upvotes: 1
Views: 65
Reputation: 89557
You can try this pattern:
^(?:[^e\n]+|\Be|\be(?!xception\b))+\.php:\d+$
or this pattern, if you don't need to check a specific line format:
^(?>[^e\n]++|\Be|\be(?!xception\b))+$
Notice: If you need to select all consecutive lines in one block, you just need to remove \n
from the character classes.
Upvotes: 2