Reputation: 189
I have a data/character_data.py:
CHARACTER_A = { 1: {"level": 1, "name":"Ann", "skill_level" : 1},
2: {"level": 2, "name":"Tom", "skill_level" : 1}}
CHARACTER_B = { 1: {"level": 1, "name":"Kai", "skill_level" : 1},
2: {"level": 2, "name":"Mel", "skill_level" : 1}}
In main.py, I can do this:
from data import character_data as character_data
print character_data.CHARACTER_A[1]["name"]
>>> output: Ann
print character_data.CHARACTER_B[2]["name"]
>>> output: Mel
How do I achieve this?
from data import character_data as character_data
character_type = "CHARACTER_A"
character_id = 1
print character_data.character_type[character_id]["name"]
>>> correct output should be: Ann
I get AttributeError when try use character_type as "CHARACTER_A".
Upvotes: 1
Views: 133
Reputation: 174622
You need to structure your data properly.
characters = {}
characters['type_a'] = {1: {"level": 1, "name":"Ann", "skill_level" : 1},
2: {"level": 2, "name":"Tom", "skill_level" : 1}}
characters['type_b'] = ...
Or, the better solution is to create your own "character" type, and use that instead:
class Character(object):
def __init__(self, type, level, name, skill):
self.type = type
self.level = level
self.name = name
self.skill = skill
characters = []
characters.append(Character('A',1,'Ann',1))
characters.append(Character('A',2,'Tom',1))
characters.append(Character('B',2,'Kai',1)) # and so on
Then,
all_type_a = []
looking_for = 'A'
for i in characters:
if i.type == looking_for:
all_type_a.append(i)
Or, the shorter way:
all_type_a = [i for i in characters if i.type == looking_for]
Upvotes: 1
Reputation: 772
How about this
In [38]: from data import character_data as character_data
In [39]: character_type = "CHARACTER_A"
In [40]: character_id = 1
In [41]: getattr(character_data, character_type)[character_id]["name"]
Out[41]: 'Ann'
Upvotes: 2
Reputation: 473903
You can use locals():
>>> from data.character_data import CHARACTER_A, CHARACTER_B
>>> character_id = 1
>>> character_type = "CHARACTER_A"
>>> locals()[character_type][character_id]["name"]
Ann
Though, think about merging CHARACTER_A
and CHARACTER_B
into one dict and access this dict instead of locals()
.
Also, see Dive into Python: locals and globals.
Upvotes: 2