CODEWITHSUNDEEP
phpforeachstr-replace
Ing. Michal Hudak
Ing. Michal Hudak

Reputation: 5612

str_replace in foreach loop

<?php 

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";

$langs = array ('sk', 'en');

foreach ($langs as $lang) {
    $search = '&lang='.$lang;    
    $new = str_replace($search, "", $url);
}

echo $new; // output: http://localhost/news

?>

Q: How to delete all parameters (&lang=en, &lang=sk) from string ?

Thank you in advance

Upvotes: 0

Views: 7906

Answers (3)

user1646111
user1646111

Reputation:

An Alternative:

First:

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";
echo preg_replace("#&lang=(en|sk)#", "", $url);

Second:

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";
echo str_replace(array("&lang=en", "&lang=sk"), "", $url);

Update: for long array of $lang:

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";
echo preg_replace("#&lang=(".implode("|", $lang).")#", "", $url);

Upvotes: 0

Liam Sorsby
Liam Sorsby

Reputation: 2982

You want to use parse_url() http://www.php.net/manual/en/function.parse-url.php and then http_build_query() http://php.net/manual/en/function.http-build-query.php

Upvotes: 0

putvande
putvande

Reputation: 15213

What you are doing is creating a new variable $new each time so that won't do anything good with the $url. Try to assign the str_replace back to its original variable like:

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";

$langs = array ('sk', 'en');

foreach ($langs as $lang) {
    $search = '&lang='.$lang;    
    $url = str_replace($search, "", $url);
}

echo $url; // output: http://localhost/news

Upvotes: 2

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