Reputation: 45
I'm trying to create 2 storyboards, one for iPhone 4 and one for iPhone 5. I want it to be detected at launch which device the user is using. I've used the following code and implemented it in my app delegate.m, but receive the error:
Use of undeclared identifier "initializeStoryBoardBasedOnScreenSize"
Here's the code I've used:
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
-(void)initializeStoryBoardBasedOnScreenSize {
if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
{ // The iOS device = iPhone or iPod Touch
CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
if (iOSDeviceScreenSize.height == 480)
{ // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35
UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone35" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
}
if (iOSDeviceScreenSize.height == 568)
{ // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone4" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
}
} else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)
{ // The iOS device = iPad
UISplitViewController *splitViewController = (UISplitViewController *)self.window.rootViewController;
UINavigationController *navigationController = [splitViewController.viewControllers lastObject];
splitViewController.delegate = (id)navigationController.topViewController;
}
Is there maybe something I need to import to fix the error?
Upvotes: 1
Views: 1007
Reputation: 539685
You have tried to define a method inside application:didFinishLaunchingWithOptions:
:
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
-(void)initializeStoryBoardBasedOnScreenSize {
// ... your code ...
}
return YES;
}
This is not what you want and btw. nested functions (or methods) are not supported in Objective-C.
What you probably meant is to define a method and call it
inside application:didFinishLaunchingWithOptions:
:
-(void)initializeStoryBoardBasedOnScreenSize {
// ... your code ...
}
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
[self initializeStoryBoardBasedOnScreenSize];
return YES;
}
Upvotes: 1
Reputation: 6079
maybe it could just be an error here, but you're entering an action void in didFinishApplicationLaunchingWithOptions?
did you try to fit everything in didFinishApplicationLaunchingWithOptions without simply use this action void?
Upvotes: 0