Reputation: 575
I have a table that contains 4 columns and in the 5th column I want to store the count of how many non-null columns there are out of the previous 4. For example:
Where X is any value:
Column1 | Column2 | Column3 | Column4 | Count
X | X | NULL | X | 3
NULL | NULL | X | X | 2
NULL | NULL | NULL | NULL | 0
Upvotes: 38
Views: 49429
Reputation: 21
That would require you to run an UPDATE
query for the Count
column every time any of the rest of the columns are updated or maybe you could set up a trigger if your DB enables you to.
If you're looking to create such a view then the following query would do just fine,
SELECT
Column1,
Column2,
Column3,
Column4,
(
COALESCE((CASE WHEN Column1 IS NOT NULL THEN 1 ELSE 0 END), 0)
+ COALESCE((CASE WHEN Column2 IS NOT NULL THEN 1 ELSE 0 END), 0)
+ COALESCE((CASE WHEN Column3 IS NOT NULL THEN 1 ELSE 0 END), 0)
+ COALESCE((CASE WHEN Column4 IS NOT NULL THEN 1 ELSE 0 END), 0)
) AS Count
FROM some_table;
Upvotes: 2
Reputation: 117345
select
T.Column1,
T.Column2,
T.Column3,
T.Column4,
(
select count(*)
from (values (T.Column1), (T.Column2), (T.Column3), (T.Column4)) as v(col)
where v.col is not null
) as Column5
from Table1 as T
Upvotes: 47
Reputation: 18411
SELECT Column1,
Column2,
Column3,
Column4,
CASE WHEN Column1 IS NOT NULL THEN 1 ELSE 0 END +
CASE WHEN Column2 IS NOT NULL THEN 1 ELSE 0 END +
CASE WHEN Column3 IS NOT NULL THEN 1 ELSE 0 END +
CASE WHEN Column4 IS NOT NULL THEN 1 ELSE 0 END AS Column5
FROM Table
Upvotes: 30
Reputation: 280262
SELECT Column1, Column2, Column3, Column4,
Column5 = LEN(COALESCE(LEFT(Column1,1),''))
+ LEN(COALESCE(LEFT(Column2,1),''))
+ LEN(COALESCE(LEFT(Column3,1),''))
+ LEN(COALESCE(LEFT(Column4,1),''))
FROM dbo.YourTable;
Demo:
DECLARE @x TABLE(a VARCHAR(32),b INT,c VARCHAR(32),d VARCHAR(32));
INSERT @x VALUES
('01',3023,NULL,'blat'),
('02',NULL, NULL,'blat'),
('03',5,NULL,'blat'),
('04',24,'bo','blat'),
(NULL, NULL, NULL, NULL);
SELECT a, b, c, d,
LEN(COALESCE(LEFT(a,1),''))
+ LEN(COALESCE(LEFT(b,1),''))
+ LEN(COALESCE(LEFT(c,1),''))
+ LEN(COALESCE(LEFT(d,1),''))
FROM @x;
Upvotes: 4