CODEWITHSUNDEEP
bashsed
msd_2
msd_2

Reputation: 1187

sed output blank in bash script

I have a file which consists of following hundred lines in addition to other data

(abc-wxyz1/2222 1234)

1234 is a random number which is different for all the 100 lines. I want to substitute all the lines with

(abc-wxyz1/2222 *)

I am using following code for it

 cat input.txt | \
     sed -i -e 's/\(abc\-wxyz1\/2222\ [0-9]\+\)/\(abc\-wxyz1\/2222\ \*\)/g' > output.txt

I get the output.txt blank I have no clue why. Am I doing it correctly ?

Upvotes: 1

Views: 1105

Answers (3)

Costi Ciudatu
Costi Ciudatu

Reputation: 38195

For the input sample you've shown, you could go with awk:

awk '{print $1 " *)"}' input.txt

Upvotes: 1

naisanza
naisanza

Reputation: 124

Use this command to see what will be the result of filter:

cat input.txt | sed 's/\(abc\-wxyz1\/2222\ [0-9]\+\)/\(abc\-wxyz1\/2222\ \*\)/g'

Try using shorter patterns to toubleshoot where it is breaking.

You only need the '-e' flag if you have additional commands to run. You could also just do:

sed 'command;command2;{command3}'

Upvotes: 0

Rubens
Rubens

Reputation: 14778

If you're going to use the flag -i, --in place, you don't have to redirect the output. The substitutions are performed in place, as expected.

Yet, you can simplify your expression, doing:

sed -i -e 's/abc\-wxyz1\/2222\ \([0-9]\+\)/*/g' input.txt

Upvotes: 0

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