Reputation: 299
I use:
BorderLayout a = new BorderLayout();
setLayout(a);
JPanel b = new JPanel();
now, if I use:
JButton c = new JButton("Press");
b.add(c);
add("East", b);
my JButton will appear normally. BUT if I say instead:
JLabel c = new JLabel();
c.setBackground(Color.BLACK);
c.setOpaque(true);
add("East", b);
my black JLabel won't appear, which I want to. Why does this happen? Thanks a lot
Upvotes: 1
Views: 149
Reputation: 324197
JLabel c = new JLabel();
You have an empty label, so I'm guessing the size if (0, 0) and there is nothing to paint. Try adding some text.
Also the following is incorrect:
add("East", b);
That is the old way of adding a constraint. Don't use hardcoded values and the constraint is specified second:
add(b, BorderLayout.???);
Read the BorderLayout API or the Swing tutorial on Using a Border Layout
for the appropriate constraint.
Upvotes: 3