CODEWITHSUNDEEP
java
Raf Nicdao
Raf Nicdao

Reputation: 115

Error: ')' expected Error: illegal start of expression

//8.    
//----------------------------------------------------------------
//-------- Display orignal and encrypted message information
//----------------------------------------------------------------
    private void displayEncryptedMessage(String originalMessage, String encryptedMessage) {
        System.out.println("");
        System.out.println("");
        System.out.println("");
        System.out.println("Enter Message to be encrypted: ");
        System.out.println("");
        System.out.println("");
        System.out.println("");
        System.out.println("   Plain Text : " + originalMessage);

    }

// 9
//----------------------------------------------------------------
// Encrypted it by substituting the character with the corresponding character in the cipher.
// 
//----------------------------------------------------------------
    private void encrypt(String cipher){
      int letterPosition;
      String encryptedMessage = "";
      String originalMessage = Keyboard.readInput();

      displayEncryptedMessage(String originalMessage, String encryptedMessage);

      for (letterPosition=0; letterPosition<originalMessage.length(); letterPosition++){
        char replaceCipherLetter = cipher.charAt(letterPosition);
        encryptedMessage += replaceCipherLetter;}
      System.out.println("   Cipher Text: " + encryptedMessage);
      }

Im really new to Java so all your comments will be GREATLY appreciated... SInce method 8. is void, it doesnt return any values right? If I wanted to put 8 into 9, displayEncryptedMessage(String originalMessage, String encryptedMessage); , is that what Id put as the parameters ? and why do I get these errors? 

  Error: ')' expected 
  Error: illegal start of expression

Upvotes: 0

Views: 304

Answers (2)

Gaurav Gupta
Gaurav Gupta

Reputation: 4701

While calling the method, you need to pass the values like:

displayEncryptedMessage(originalMessage, encryptedMessage);

Declaring the type of parameter that method will accept, is part of method definition.

Note: Method can also accept the Type or Subtype of the type.

Upvotes: 0

saurav
saurav

Reputation: 3462

When you are calling the method , you have to only pass the values , type declaration is not allowed while method calling.

displayEncryptedMessage(String originalMessage, String encryptedMessage);

should be

 displayEncryptedMessage(originalMessage, encryptedMessage);

Upvotes: 11

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