CODEWITHSUNDEEP
bash
Stefan Ludwig
Stefan Ludwig

Reputation: 363

Iterating over files with optional leading dots, without using shopt -s dotglob

In a bash script, I'd like to list all files matching a string, including those with a leading dot.

E.g.

    ls -A

gives me

    .bla.0  .bla.1  bla.2   bla.3

and I'd like to have an expression of the sort

    for f in <whatgoeshere?>${pat}* ; do
      <something with $f>
    done

I have tried to use

    shopt -s extglob

and some form of ?(.)bla* and ?(\.)bla*, but to no avail.

I could use

    shopt -s dotglob

but I was wondering, if there's a way to specify the pattern without using that.

This would work, but is not very elegant:

    for f in `shopt -s dotglob ; ls -A *${pat}*` ; do echo $f; done

Upvotes: 1

Views: 113

Answers (3)

Craig
Craig

Reputation: 4399

You don't need extglobs. Just use something like this:

for f in {.,}${pat}* ; do
    [[ $f == "." || $f == ".." ]] && continue
    echo $f
done

Update:

If you anticipate files with spaces in the name, go with the find based solution.

Upvotes: 2

Jan Matejka
Jan Matejka

Reputation: 1970

pat=bla

for i in .${pat}* ${pat}*; do
    echo $i
done

Upvotes: 2

anubhava
anubhava

Reputation: 785866

You can replace your ls -A command with find with -regex switch like this:

while read f; do echo $f; done < <(find . -maxdepth 1 -regex ".*${pat}.*")

Upvotes: 2

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