CODEWITHSUNDEEP
ruby
Shpigford
Shpigford

Reputation: 25338

Drop everything from a string before a specific word?

How can I remove everything in a string before a specific word (or including the first space and back)?

I have a string like this:

12345 Delivered to: Joe Schmoe

I only want Delivered to: Joe Schmoe

So, basically anything from the first space and back I don't want.

I'm running Ruby 1.9.3.

Upvotes: 0

Views: 89

Answers (3)

tigeravatar
tigeravatar

Reputation: 26640

If Delivered isn't always the 2nd word, you can use this way:

s_line = "12345 Delivered to: Joe Schmoe"
puts s_line[/\s.*/].strip #=> "Delivered to: Joe Schmoe"

Upvotes: 0

Alex Peachey
Alex Peachey

Reputation: 4676

Quite a few different ways are possible. Here are a couple:

s = '12345 Delivered to: Joe Schmoe'
s.split(' ')[1..-1].join(' ') # split on spaces, take the last parts, join on space
# or
s[s.index(' ')+1..-1] # Find the index of the first space and just take the rest
# or
/.*?\s(.*)/.match(s)[1] # Use a reg ex to pick out the bits after the first space

Upvotes: 0

Guilherme Bernal
Guilherme Bernal

Reputation: 8293

Use a regex to select just the part of the string you want.

"12345 Delivered to: Joe Schmoe"[/Delive.*/]
# => "Delivered to: Joe Schmoe"

Upvotes: 3

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