Reputation: 1583
As an intermediate R user, I know that for loops can very often be optimized by using functions like apply
or otherwise. However, I am not aware of functions that can optimize my current code to generate a markov chain matrix, which is running quite slowly. Have I max-ed out on speed or are there things that I am overlooking? I am trying to find the transition matrix for a Markov chain by counting the number of occurrences in 24-hour time periods before given alerts. The vector ids
contains all possible id's (about 1700).
The original matrix looks like this, as an example:
>matrix
id time
1 1376084071
1 1376084937
1 1376023439
2 1376084320
2 1372983476
3 1374789234
3 1370234809
And here is my code to try to handle this:
matrixtimesort <- matrix[order(-matrix$time),]
frequency = 86400 #number of seconds in 1 day
# Initialize matrix that will contain probabilities
transprobs <- matrix(data=0, nrow=length(ids), ncol=length(ids))
# Loop through each type of event
for (i in 1:length(ids)){
localmatrix <- matrix[matrix$id==ids[i],]
# Loop through each row of the event
for(j in 1:nrow(localmatrix)) {
localtime <- localmatrix[j,]$time
# Find top and bottom row number defining the 1-day window
indices <- which(matrixtimesort$time < localtime & matrixtimesort$time >= (localtime - frequency))
# Find IDs that occur within the 1-day window
positiveids <- unique(matrixtimesort[c(min(indices):max(indices)),]$id)
# Add one to each cell in the matrix that corresponds to the occurrence of an event
for (l in 1:length(positiveids)){
k <- which(ids==positiveids[l])
transprobs[i,k] <- transprobs[i,k] + 1
}
}
# Divide each row by total number of occurrences to determine probabilities
transprobs[i,] <- transprobs[i,]/nrow(localmatrix)
}
# Normalize rows so that row sums are equal to 1
normalized <- transprobs/rowSums(transprobs)
Can anyone make any suggestions to optimize this for speed?
Upvotes: 1
Views: 877
Reputation: 873
Using nested loops seems a bad idea. Your code can be vectorized to speed up.
For example, why find the top and bottom of row numbers? You can simply compare the time value with "time_0 + frequency": it is a vectorized operation.
HTH.
Upvotes: 0