CODEWITHSUNDEEP
pythonstringsubstring
Johnny Chen
Johnny Chen

Reputation: 2070

How to sub the file path to get just the file name?

I have a lot of strings like this 

/home/build_targets/JavaFiles/Commonfeature/CM/src/com/ems/ClusterGroupTreePanel.java

I need to get the file name ClusterGroupTreePanel.java out.

Is there an efficient way to achieve this in Python?

Upvotes: 0

Views: 78

Answers (3)

Ashwani
Ashwani

Reputation: 3481

This way:

 >>> str = '/home/build_targets/JavaFiles/Commonfeature/CM/src/com/ems/ClusterGroupTreePanel.java'
 >>> s = str.rfind('/')     
 >>> name = str[s:]

Upvotes: 0

eran
eran

Reputation: 6921

os.path.basename(path) will give you the file name, if you want to leave it out you can use os.path.split and take the first part

os.path.split(full_path)[0]

Upvotes: 1

mgilson
mgilson

Reputation: 309841

use os.path.basename

>>> import os.path
>>> os.path.basename('/home/build_targets/JavaFiles/Commonfeature/CM/src/com/ems/ClusterGroupTreePanel.java')
'ClusterGroupTreePanel.java'

Generally, if your question goes something like "How do I manipulate this filesystem path name in an interesting way?". The answer is usually "use some combination of functions in the os.path module". There's lots of great stuff in there and it would be well worth your time to familiarize yourself with the different functions.

Upvotes: 4

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