CODEWITHSUNDEEP
ajaxhtmlfile-uploadxmlhttprequestmultipartform-data
Max Ehrlich
Max Ehrlich

Reputation: 2525

JavaScript Blob Upload with FormData

I am having a problem uploading a blob created in javascript to my server. The basic idea is that a user uploads an image and in javascript I center crop the image and downsample it before transmission.

The image manipulation is working fine, but the upload itself is not working right. Here is the code that does the upload and conversion from canvas to blob

function uploadCanvasData()
{
    var canvas = $('#ImageDisplay').get(0);
    var dataUrl = canvas.toDataURL("image/jpeg");

    var blob = dataURItoBlob(dataUrl);

    var formData = new FormData();
    formData.append("file", formData);

    var request = new XMLHttpRequest();
    request.onload = completeRequest;

    request.open("POST", "IdentifyFood");
    request.send(formData);
}

function dataURItoBlob(dataURI)
{
    var byteString = atob(dataURI.split(',')[1]);

    var mimeString = dataURI.split(',')[0].split(':')[1].split(';')[0]

    var ab = new ArrayBuffer(byteString.length);
    var ia = new Uint8Array(ab);
    for (var i = 0; i < byteString.length; i++)
    {
        ia[i] = byteString.charCodeAt(i);
    }

    var bb = new Blob([ab], { "type": mimeString });
    return bb;
}

The server claims that no files were uploaded, and when I use chrome to examine the request, I see the request payload as:

------WebKitFormBoundaryyzYbm61DKgS09tpB
Content-Disposition: form-data; name="file"

[object FormData]
------WebKitFormBoundaryyzYbm61DKgS09tpB--

In contrast to the payload of a form being submitted with input type="file"

------WebKitFormBoundaryUOn3WXb7pKLmOxRZ
Content-Disposition: form-data; name="imagefile"; filename="-3YQHiVaGWo.jpg"
Content-Type: image/jpeg


------WebKitFormBoundaryUOn3WXb7pKLmOxRZ--

So it looks to me like the XMLHttpRequest is just uploading the result of calling blob.toString()

Does anyone know what I am doing wrong here? Is there a better approach I should be using?

Upvotes: 35

Views: 47029

Answers (2)

Ir Calif
Ir Calif

Reputation: 478

function dataURItoBlob(dataURI) {
// convert base64/URLEncoded data component to raw binary data held in a string
var byteString;
if (dataURI.split(',')[0].indexOf('base64') >= 0)
    byteString = atob(dataURI.split(',')[1]);
else
    byteString = unescape(dataURI.split(',')[1]);

// separate out the mime component
var mimeString = dataURI.split(',')[0].split(':')[1].split(';')[0];

// write the bytes of the string to a typed array
var ia = new Uint8Array(byteString.length);
for (var i = 0; i < byteString.length; i++) {
    ia[i] = byteString.charCodeAt(i);
}

return new Blob([ia], {type:mimeString});
}

create an xmlhttpRequest

let uriPost   ="active.php";
let xhrPost   =new XMLHttpRequest();

then do this it easy

var dataURL = canvas.toDataURL('image/jpeg', 0.5);
var blob = dataURItoBlob(dataURL);
var fd = new FormData(document.forms[0]);
fd.append("canvasImage", blob);

I hope you'l do all this in a function that you will create your self then call that function

Upvotes: 2

Max Ehrlich
Max Ehrlich

Reputation: 2525

You have a typo in the function uploadCanvasData it should read

formData.append("file", blob);

Read your code more carefully!

Upvotes: 48

Related Questions