Reputation: 11407
I have duplicate rows in my table, how can I delete them based on a single column's value?
Eg
uniqueid, col2, col3 ...
1, john, simpson
2, sally, roberts
1, johnny, simpson
delete any duplicate uniqueIds
to get
1, John, Simpson
2, Sally, Roberts
Upvotes: 10
Views: 43491
Reputation: 21
Here is simple magic to remove duplicates
select * into NewTable from ExistingTable
union
select * from ExistingTable;
Upvotes: 2
Reputation: 11
You have many ways for deleting the duplicate records some of them are below...........
Different ways to delete Duplicate records
Using Row_Number() function and CTE
with CTE(DuplicateCount) as ( SELECT ROW_NUMBER() OVER
(PARTITION by UniqueId order by UniqueId ) as DuplicateCount from
Table1 ) Delete from CTE where DuplicateCount > 1
.Without using CTE*
Delete DuplicateCount from ( Select Row_Number() over(Partition by
UniqueId order by UniqueId) as Dup from Table1 ) DuplicateCount
where DuplicateCount.Dup > 1
.Without using row_Number() and CTE
Delete from Subject where RowId not in(select Min(RowId ) from
Subject group by UniqueId)
Upvotes: 1
Reputation: 731
You probably have a row id that is assigned by the DB upon insertion and is actually unique. I'll call this rowId in my example.
rowId |uniqueid |col2 |col3
----- |-------- |---- |----
1 10 john simpson
2 20 sally roberts
3 10 johnny simpson
You can remove duplicates by grouping on the thing that is supposed to be unique (whether it be one column or many), then you grab a rowId from each group, and delete everything else besides those rowIds. In the inner query, everything in the table will have a rowId except for the duplicate rows.
select *
--DELETE
FROM MyTable
WHERE rowId NOT IN
(SELECT MIN(rowId)
FROM MyTable
GROUP BY uniqueid);
You could also use MAX instead of MIN with similar results.
Upvotes: 3
Reputation: 34774
You can DELETE
from a cte:
WITH cte AS (SELECT *,ROW_NUMBER() OVER(PARTITION BY uniqueid ORDER BY col2)'RowRank'
FROM Table)
DELETE FROM cte
WHERE RowRank > 1
The ROW_NUMBER()
function assigns a number to each row. PARTITION BY
is used to start the numbering over for each item in that group, in this case each value of uniqueid
will start numbering at 1 and go up from there. ORDER BY
determines which order the numbers go in. Since each uniqueid
gets numbered starting at 1, any record with a ROW_NUMBER()
greater than 1 has a duplicate uniqueid
To get an understanding of how the ROW_NUMBER()
function works, just try it out:
SELECT *,ROW_NUMBER() OVER(PARTITION BY uniqueid ORDER BY col2)'RowRank'
FROM Table
ORDER BY uniqueid
You can adjust the logic of the ROW_NUMBER()
function to adjust which record you'll keep or remove.
For instance, perhaps you'd like to do this in multiple steps, first deleting records with the same last name but different first names, you could add last name to the PARTITION BY
:
WITH cte AS (SELECT *,ROW_NUMBER() OVER(PARTITION BY uniqueid, col3 ORDER BY col2)'RowRank'
FROM Table)
DELETE FROM cte
WHERE RowRank > 1
Upvotes: 36
Reputation: 545
DECLARE @du TABLE (
id INT,
Name VARCHAR(4)
)
INSERT INTO @du VALUES(1,'john')
INSERT INTO @du VALUES(2,'jane')
INSERT INTO @du VALUES(1,'john')
;WITH dup (id,dp)
AS
(SELECT id
, ROW_NUMBER() OVER(PARTITION BY id ORDER BY Name) AS dp
FROM @du)
DELETE FROM dup
WHERE dp > 1
SELECT *
FROM @du
Upvotes: 2
Reputation: 3407
DELETE FROM table WHERE uniqueid='1' AND col2='john'
Or you change col2='john'
to col2='johnny'
. Depends on which record you want to delete.
How did you end up with two same "unique" IDs in the first place?
Upvotes: 1