CODEWITHSUNDEEP
pythonpython-2.7
Phil
Phil

Reputation: 14671

How to capitalize each word after a space leaving the rest of it as is and preserve the space in the end if it exists

I have the following procedure:

def capitalize(self, text):
    t = ' '.join([ ''.join([w[0].upper()]+[w[1:]]) for w in text.split()])
    if text and text[-1] == ' ':
        t = ''.join([t] + [' '])
    return t

It takes a string text. What it's supposed to do:

ex:

'home swe eeeet home' -> 'Home Swe Eeeet Home'
'heLLo OoO ooo '      -> 'HeLLo OoO Ooo ' (space preserved in the end)

Question:

With my limited, totally non - expert level of Python, I tried to create this procedure as memory efficient and as fast as possible.

Furthermore:

This procedure is called each time a key is pressed onto a text field on a GUI application.

Upvotes: 2

Views: 3206

Answers (2)

freeflow
freeflow

Reputation: 1

def title(s):
    return(' '.join(x.capitalize() for x in s.split(' ')))

# Or alternatively:
#y = []
#for x in s.split(' '): 
#    y.append(x.capitalize())
#return ' '.join(y)

Upvotes: 0

falsetru
falsetru

Reputation: 369274

Use re.sub:

>>> import re
>>> re.sub(r'\b[a-z]', lambda m: m.group().upper(), 'home swe eeeet home')
'Home Swe Eeeet Home'
>>> re.sub(r'\b[a-z]', lambda m: m.group().upper(), 'heLLo OoO ooo ')
'HeLLo OoO Ooo '

re.sub(pattern, repl, string, count=0, flags=0)

Return the string obtained by replacing the leftmost non-overlapping occurrences of pattern in string by the replacement repl. If the pattern isn’t found, string is returned unchanged. repl can be a string or a function.

If repl is a function, it is called for every non-overlapping occurrence of pattern. The function takes a single match object argument, and returns the replacement string.

\b[a-z] match any lowercase character([a-z]) after the word boundary (\b).

The lambda function was used to convert the character to uppercase; MatchObject.match return match group. Without argument group 0 is assumed. Group 0 mean entire match string.

Upvotes: 2

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