CODEWITHSUNDEEP
javajava.util.scanner
Yinyin Wang
Yinyin Wang

Reputation: 47

Scanner nextInt() doesn't return all integers in string?

I have a string currLine = "0 1435 " 3029 " "(1975.92)" " 72,304"" (there are quotations within the string) and I want to print out all of the integers in currLine. But with the code below, I only get the number 0 printed out. How do I use nextInt() so that it prints out all of the integers?

        Scanner scanLine = new Scanner(currLine);           
        while (scanLine.hasNext()) {
            if (scanLine.hasNextInt()) {
                System.out.println(scanLine.nextInt());
            }
            scanLine.next();
        }

Upvotes: 1

Views: 376

Answers (3)

arshajii
arshajii

Reputation: 129497

As soon as the Scanner encounters something that isn't an int, hasNextInt() returns false. Not to mention the fact that you're skipping over some valid ints with the scanLine.next() call at the bottom of your while-loop. You can use a Matcher instead:

Matcher m = Pattern.compile("\\d+").matcher(currLine);
while (m.find()) {
    System.out.println(m.group());
}

0
1435
3029
1975
92
72
304

Upvotes: 4

Grief
Grief

Reputation: 2040

Actually, else word is missing too. No need to do next() if nextInt() done.

Upvotes: 1

DanielD
DanielD

Reputation: 28

I believe next() goes until it sees a space. I would use replace("\"",""), rinse and repeat with other characters until you have a string of the integers you can print.

Upvotes: 0

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