CODEWITHSUNDEEP
javaregex
user2664353
user2664353

Reputation: 127

How to write regex for bullet space digit and dot

I am using regex for my sentence contains bullet space digit and dot.

• 1. This is sample Application
• 2. This is Sample java program

regex: 

•\\s\\d\\.\\s[A-z]

Required output:
This is sample Application.
This is Sample java program.

its not working.Please Suggest me how to do this.

Upvotes: 7

Views: 16750

Answers (4)

isaacparrot
isaacparrot

Reputation: 2053

Instead of using the actual 'bullet,' use the unicode equivalent:

\u2022\s\d\.\s[A-z]

For more info see Unicode Character 'BULLET' (U+2022) and Regex Tutorial - Unicode Characters and Properties

EDIT: To split the lines (assuming each line is a separate string) try this out:

String firstString = "• 1. This is sample Application";
System.out.println(firstString.split("\\u2022\\s\\d\\.\\s")[1]);

This works because String.split cuts your string into an array wherever there's a match. The [1] addresses the second item in that array, being the second half of the split.

Upvotes: 3

diestl
diestl

Reputation: 2058

To match the bullet character you will need to use the unicode escape sequence. However Unicode defines several bullet styles, so it's probably best to allow for all of them:

[\u2022,\u2023,\u25E6,\u2043,\u2219]\s\d\.\s[A-z]

This should match the following bullet styles:

  • Bullet (•)
  • Triangular Bullet (‣)
  • White Bullet (◦)
  • Hyphen Bullet (⁃)
  • Bullet Operator (∙)

Reference: https://en.wikipedia.org/wiki/%E2%80%A2

Upvotes: 15

Angga
Angga

Reputation: 2323

use this

String a="• 1. This is sample Application";
a = a.replaceAll("\\u2022(?=\\s\\d\\.\\s[A-z])",""); // this will remove the • if only the bulet have \\s\\d\\.\\s[A-z] patern after it.
System.out.println(a);

Upvotes: 1

Ruchira Gayan Ranaweera
Ruchira Gayan Ranaweera

Reputation: 35557

Why regex? you can use this way

   String str="• 1. This is sample Application";
   String newStr=str.replaceAll("\\•|\\.",""); 
   // Or str.replaceAll("\\u2022|\\.","");u2022 is unicode value of bullet 
   System.out.println(newStr);

Upvotes: 0

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