CODEWITHSUNDEEP
php
Letter
Letter

Reputation: 819

PHP date add 5 year to current date

I have this PHP code:

$end=date('Y-m-d');

I use it to get the current date, and I need the date 5 years in the future, something like:

$end=date('(Y + 5)-m-d');

How can I do this?

Upvotes: 81

Views: 219074

Answers (12)

Divyesh
Divyesh

Reputation: 161

Try this code:

<?php
$current_date=strtotime(date('Y-m-d'));

echo $end = date('Y-m-d', strtotime('+5 years',$current_date));

?>

Upvotes: 2

Bijaya Prasad Kuikel
Bijaya Prasad Kuikel

Reputation: 322

Its very very easy with Carbon.

$date = "2016-02-16"; // Or Your date
$newDate    = Carbon::createFromFormat('Y-m-d', $date)->addYear(1);

Upvotes: 8

Nirav
Nirav

Reputation: 109

$date = strtotime($row['timestamp']);
$newdate = date('d-m-Y',strtotime("+1 year",$date));

Upvotes: 9

Tuncay Elvanagac
Tuncay Elvanagac

Reputation: 1332

You may use DateInterval for this purpose;

$currentDate = new \DateTime(); //creates today timestamp
$currentDate->add(new \DateInterval('P5Y')); //this means 5 Years
and you can now format it;
$currentDate->format('Y-m-d');

Upvotes: 2

Rahul Gandhi
Rahul Gandhi

Reputation: 19

Try this code and add next Days, Months and Years

// current month: Aug 2018
$n = 2;
for ($i = 0; $i <= $n; $i++){
   $d = strtotime("$i days");
   $x = strtotime("$i month");
   $y = strtotime("$i year");
   echo "Dates : ".$dates = date('d M Y', "+$d days");
   echo "<br>";
   echo "Months : ".$months = date('M Y', "+$x months");
   echo '<br>';
   echo "Years : ".$years = date('Y', "+$y years");
   echo '<br>';
}

Upvotes: 0

GoldTechnia Pvt. Ltd.
GoldTechnia Pvt. Ltd.

Reputation: 11

try this:

$yearnow= date("Y");
$yearnext=$yearnow+1;
echo date("Y")."-".$yearnext;

Upvotes: 0

RN Kushwaha
RN Kushwaha

Reputation: 2136

Use this code to add years or months or days or hours or minutes or seconds to a given date

 echo date("Y-m-d H:i:s", strtotime("+1 years", strtotime('2014-05-22 10:35:10'))); //2015-05-22 10:35:10
 echo date("Y-m-d H:i:s", strtotime("+1 months", strtotime('2014-05-22 10:35:10')));//2014-06-22 10:35:10
 echo date("Y-m-d H:i:s", strtotime("+1 days", strtotime('2014-05-22 10:35:10')));//2014-05-23 10:35:10
 echo date("Y-m-d H:i:s", strtotime("+1 hours", strtotime('2014-05-22 10:35:10')));//2014-05-22 11:35:10
 echo date("Y-m-d H:i:s", strtotime("+1 minutes", strtotime('2014-05-22 10:35:10')));//2014-05-22 10:36:10
 echo date("Y-m-d H:i:s", strtotime("+1 seconds", strtotime('2014-05-22 10:35:10')));//2014-05-22 10:35:11

You can also subtract replacing + to -

Upvotes: 15

Abhi
Abhi

Reputation: 1115

try this ,

$presentyear = '2013-08-16 12:00:00';

$nextyear  = date("M d,Y",mktime(0, 0, 0, date("m",strtotime($presentyear )),   date("d",strtotime($presentyear )),   date("Y",strtotime($presentyear ))+5));

echo $nextyear;

Upvotes: 1

Gadoma
Gadoma

Reputation: 6565

Modifying dates based on this post
strtotime() is really powerful and allows you to modify/transform dates easily with it’s relative expressions too:

Procedural

    $dateString = '2011-05-01 09:22:34';
    $t = strtotime($dateString);
    $t2 = strtotime('-3 days', $t);
    echo date('r', $t2) . PHP_EOL; // returns: Thu, 28 Apr 2011 09:22:34 +0100

DateTime

    $dateString = '2011-05-01 09:22:34';
    $dt = new DateTime($dateString);
    $dt->modify('-3 days');
    echo $dt->format('r') . PHP_EOL; // returns: Thu, 28 Apr 2011 09:22:34 +0100

The stuff you can throw at strtotime() is quite surprising and very human readable. Have a look at this example looking for Tuesday next week.

Procedural

    $t = strtotime("Tuesday next week");
    echo date('r', $t) . PHP_EOL; // returns: Tue, 10 May 2011 00:00:00 +0100

DateTime

    $dt = new DateTime("Tuesday next week");
    echo $dt->format('r') . PHP_EOL; // returns: Tue, 10 May 2011 00:00:00 +0100

Note that these examples above are being returned relative to the time now. The full list of time formats that strtotime() and the DateTime constructor takes are listed on the PHP Supported Date and Time Formats page.

Another example, suitable for your case could be: based on this post 

    <?php
    //How to get the day 3 days from now:
    $today = date("j");
    $thisMonth = date("n");
    $thisYear = date("Y");
    echo date("F j Y", mktime(0,0,0, $thisMonth, $today+3, $thisYear)); 

    //1 week from now:
    list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
    echo date("F j Y", mktime(0,0,0, $thisMonth, $today+7, $thisYear));

    //4 months from now:
    list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
    echo date("F j Y", mktime(0,0,0, $thisMonth+4, $today, $thisYear)); 

    //3 years, 2 months and 35 days from now:
    list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
    echo date("F j Y", mktime(0,0,0, $thisMonth+2, $today+35, $thisYear+3));
    ?>

Upvotes: 30

hsz
hsz

Reputation: 152206

Try with:

$end = date('Y-m-d', strtotime('+5 years'));

Upvotes: 180

ciruvan
ciruvan

Reputation: 5213

Using Carbon:

$dt = Carbon::now();
echo $dt->addYears(5);

Upvotes: 3

웃웃웃웃웃
웃웃웃웃웃

Reputation: 11984

To add one year to todays date use the following:

$oneYearOn = date('Y-m-d',strtotime(date("Y-m-d", mktime()) . " + 365 day"));

Upvotes: 1

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