CODEWITHSUNDEEP
asp.net-mvcasp.net-mvc-4
kroiz
kroiz

Reputation: 1772

ASP.NET MVC: Multiple submit buttons using Ajax.BeginForm

I want to create a page that has a next button and previous button that switches the image displayed.

For that purpose I created an Ajax.BeginForm and inserted into it, an image and two submit buttons.

Can I (should I) have multiple submit buttons inside an Ajax.BeginForm?

How would the controller handle each submit separately?

Upvotes: 13

Views: 25816

Answers (3)

citronsmurf
citronsmurf

Reputation: 90

I had the same requirement/issue and tried both solutions here and they both work for me. I LIKE the idea of setting the action via jquery when clicking so I can keep my actions separate so they can be used by other views.

HOWEVER, I've found that when I do this while I debug, it posts TWICE and BOTH the OnSuccess and OnFailure are triggered. It only happens when debugging though. Keep this in mind when picking.

Upvotes: 1

Jaimin
Jaimin

Reputation: 8020

Try this,

View

@model TwoModelInSinglePageModel.RegisterModel
@using (Ajax.BeginForm("DYmanicControllerPage", "Test", FormMethod.Post,null, new { id = "frmSignUp" }))
{ 
  <div>
                <input type="hidden" id="" name="hidden2" id="hdasd" />
                @Html.HiddenFor(m => m.hidden1)
                @Html.LabelFor(m => m.Name)
                @Html.TextBoxFor(m => m.Name)
                @Html.ValidationMessageFor(m => m.Name)
            </div>
            <br />
            <div>
                @Html.LabelFor(m => m.Address)
                @Html.TextBoxFor(m => m.Address)
                @Html.ValidationMessageFor(m => m.Address)
            </div>
            <br />
            <div>
                @Html.LabelFor(m => m.PhoneNo)
                @Html.TextBoxFor(m => m.PhoneNo)
                @Html.ValidationMessageFor(m => m.PhoneNo)
            </div>

 <input type="submit" value="Save"  id="btnSave" name="ButtonType"/>
 <input type="submit" value="Next"  id="btnNext" name="ButtonType" />


}

Controller

  [HttpPost]
        public ActionResult DYmanicControllerPage(RegisterModel model,  string ButtonType)
        {
        if(ButtonType == "Next")
        {
            // Do Next Here
        }
        if (ButtonType == "Save")
        {
            //Do save here
        }
        return JavaScript("REturn anything()");

        }

Upvotes: 28

Sam
Sam

Reputation: 15771

I would recommend that you have two buttons and then depending on what button was clicked you could set the action on the form:

Razor

$(function (){
    $("#btn-prev").click(function() {
        $("#form").attr
                   (
                      "action",
                      "@Url.Action("Action", "Controller", new {area="Area" })", 
                   ).submit();
    });
    $("#btn-next").click(function() {
        $("#form").attr
                   (
                      "action",
                      "@Url.Action("Action", "Controller", new {area="Area" })", 
                   ).submit();
    });
});

I am using jQuery here to do this, but I think you can get the idea.

Upvotes: 7

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