Reputation: 135
My message bit is 10011010
, so code word for this is 0110
and now the codeword is 011100101010
.
Suppose the error is in 10th bits and it becomes 011100101110
, so finding parity bits:
p1=1+3+5+7+9+11=010111=even number of 1 therefore=0
p2=2+3+6+7+10+11=110111=1
p4=4+5+6+7=1001=0
p8=8+9+10+11+12=01110=1
Comparing with the message the parity is false for 4 and 8 position ie 4+8=12, but in fact we have made errors in 10 bit. Where have I made a mistake?
Upvotes: 0
Views: 815
Reputation: 5751
It works a little bit different. When you check parity, you don't use parity bits to count it (you count them now). So:
p1 = 3+5+7+9+11 = 10111 = 0 (OK)
p2 = 3+6+7+10+11 = 10111 = 0 (WRONG)
p4 = 5+6+7 = 010 = 1 (OK)
p8 = 9+10+11+12 = 1110 = 1 (WRONG)
So 2+8 = 10
.
Upvotes: 1