Reputation: 41
I have a web form with several options for uploading photos (up to 10). ContentType
set to "multipart/form-data". I know how to upload just one file, but have no idea how to create HttpContent
for other 9 optional? Creating MultipartContent
with appropriate ContentDisposition
header gave no luck. At very best I got:
Content-Disposition: form-data; name="bla bla bla";
Or, if I add parameters to ContentDisposition
header:
Content-Disposition: form-data; name="bla bla bla"; filename;
I need to send post request with empty content for optional upload files like this:
Content-Disposition: form-data; name="bla bla bla"; filename=""
Any ideas appreciated.
Upvotes: 0
Views: 784
Reputation: 41
OK, I don't know if it is a best solution for my question, but at least it works:
1. Create new class for HttpContent (subclass from HttpContent
).
2. Initialize Content-Disposition
header.
3. Override two methods TryComputeLength
(return false) and SerializeToStreamAsync
(just a stub for serialization task).
Now this class can be added to MultipartFormDataContent
.
And http request content looks like:
----------[boundary string]
Content-Disposition: form-data; name="formFieldName"; filename=""
----------[boundary string]
Upvotes: 1