CODEWITHSUNDEEP
pythondjangofile-uploaderror-handling
Ranjeet singh
Ranjeet singh

Reputation: 794

image uploading using django

i have an code, code is running well, problem with this code is that it did not get the filename when the file is uploaded.

views.py 

@csrf_exempt
def upload_file(request):
    if request.method == 'POST':

        form = UploadFileForm(request.POST, request.FILES)
        if form.is_valid():
            handle_uploaded_file(request.FILES['file'])
        if 'filename' in request.FILES:
            filename = request.FILES['filename']
        else:
           return HttpResponseRedirect('/user_profileform/')
    else:
        form = UploadFileForm()
        return render_to_response('user_profile.html', {'form': form })

def handle_uploaded_file(f):

    destination = open('media/name', 'wb+')
    for chunk in f.chunks(): 
        destination.write(chunk)
    destination.close()

my form is :-

<form action="/user_profileform/" method="POST" enctype="multipart/form-data" name="uform" id="userform">{% csrf_token %}
{{form}}

<input type="submit" value="submit" name="usubmit">
</form>

when using this the file is uploaded properly but did not get the file name,, why.

Upvotes: 1

Views: 108

Answers (1)

Daniel Hepper
Daniel Hepper

Reputation: 29967

The issue is probably that you are trying to read the filename from the request.FILES dictionary. This dictionary contains an UploadedFile object for each file upload field in your form. The filename is a property of that UploadedFile object. Try this:

if request.FILES['file'].name:
    filename = request.FILES['file'].name

If that doesn't work, show us your actual form and the code where you are trying to use the filename.

Upvotes: 2

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