CODEWITHSUNDEEP
linuxshell
Hans
Hans

Reputation: 591

finding file size for a conditional

I'm trying to write a conditional statement so that if a file is greater than 1GB it prints the name of that file, in a file, and skips processing it.

#!/bin/bash
for f in *.dmp
do
    if [ ! $(stat -c %s $f > 1000000000) ]; then
        name=`basename ${f%.dmp}`
        if [ -f ../tshark/$name.dat ]; then
            echo "file exists, moving on...";
        else
            echo "Processing" $name;
            tshark -PVx -r "$f" > ../tshark/$name.dat;
            echo $name "complete, moving on...";
        fi
    else
        echo $f "too large";
        echo $f "\n" > tooLarge.txt;
    fi
done

The problem is ! $(stat -c %s $f > 1000000000) isn't working.

I'd appreciate any suggestions.

Upvotes: 0

Views: 104

Answers (2)

andyg0808
andyg0808

Reputation: 1403

So, if you haven't seen the Advanced Bash Scripting Guide, you should. Yes, it's focused around Bash, but it's also a great reference for things like this conditional.

Now, what you've written tries to execute stat -c %s $f > 1000000000 as a command (it's inside the parens on the $() construct, which is equivalent to the old backtick, as far as I understand. What you want is $(stat -c %s $f) -le 1000000000 which does stat -c %s $f and then checks if it's less than or equal to 1000000000. This (i.e., a<=b) is the equivalent of !(a>b) logically.

Upvotes: 2

devnull
devnull

Reputation: 123518

The problem is "! $(stat -c %s $f > 1000000000)" isn't working.

You are including the condition in your command, i.e. within $(...). Say:

"! $(stat -c %s $f) > 1000000000"

Upvotes: 1

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